maths genious

[superls]

hi i am in need of a maths genious, ive tried searching on google, my eyes and head hurt from reading and im no closer to my goal,

basically i need to work out the total permutations of the following.

there are 8 events, each event has 3 possible outcomes, hoe many permutations is there?

 

[Littlewood]

8 events
3 outcomes

8
8
8
24

24
24
24
24
24
24
24
24
192

Dont think this is right tbh, All I did was (8 x 3) x 8.

 

[Arnold]

I think it would be

3 x 3 x 3 x 3 x 3 x 3 x 3 x 3

= 6561 possible outcomes

If you break it down, it's

Row x next row and keep going, so for example, 3x3 = 9, 3x9 =27, 3x27 etc etc
1) 3
2) 9
3) 27
4) 81
5) 243
6) 729
7) 2187
8) 6561

 

[Littlewood]

I'm tryin to create a query in Excel to give me the answer lol

 

[Arnold]

it's just 3^8

 

[curtis]

it's just 3^8

Agreed with Arnold...

 

[Littlewood]

PERMUT

Returns the number of permutations for a given number of objects that can be selected from number objects. A permutation is any set or subset of objects or events where internal order is significant. Permutations are different from combinations, for which the internal order is not significant. Use this function for lottery-style probability calculations.

Syntax

PERMUT(number,number_chosen)

Number is an integer that describes the number of objects.

Number_chosen is an integer that describes the number of objects in each permutation.

Remarks

Both arguments are truncated to integers.
If number or number_chosen is nonnumeric, PERMUT returns the #VALUE! error value.
If number ≤ 0 or if number_chosen < 0, PERMUT returns the #NUM! error value.
If number < number_chosen, PERMUT returns the #NUM! error value.
The equation for the number of permutations is:

P k,n = n!
___
(n-k)!

__________

Which is what Arnold said,

 

[Craig]

This is not some kind of sports bet is it?

 

[eltaylor001]

Littlewood has the correct formula. n factorial divided by n-k factorial. This makes the answer as follows:

1. 8! divided by (8-3)!
2. 8! divided by 5!
3. (8x7x6x5x4x3x2x1) divided by (5x4x3x2x1)
4. 40320/120
5. 336

 

[Arnold]

Why would you subtract the number of outcomes from the number of events?

Just to show you my method is correct, i wrote out the first four events

Event 1 (Three Outcomes)

1 2 3

Event 2 (Nine Outcomes)

1 1
1 2
1 3
2 1
2 2
2 3
3 1
3 2
3 3

Event 3 (Twenty Seven Outcomes)

1 1 1
1 1 2
1 1 3
1 2 1
1 2 2
1 2 3
1 3 1
1 3 2
1 3 3
2 1 1
2 1 2
2 1 3
2 2 1
2 2 2
2 2 3
2 3 1
2 3 2
2 3 3
3 1 1
3 1 2
3 1 3
3 2 1
3 2 2
3 2 3
3 3 1
3 3 2
3 3 3

Event 4 (81 Outcomes)

1 1 1 1
1 1 1 2
1 1 1 3
1 1 2 1
1 1 2 2
1 1 2 3
1 2 3 1
1 2 3 2
1 2 3 3
1 2 1 1
1 2 1 2
1 2 1 3
1 2 2 1
1 2 2 2
1 2 2 3
1 2 3 1
1 2 3 2
1 2 3 3
1 3 1 1
1 3 1 2
1 3 1 3
1 3 2 1
1 3 2 2
1 3 2 3
1 3 3 1
1 3 3 2
1 3 3 3

2 1 1 1
2 1 1 2
2 1 1 3
2 1 2 1
2 1 2 2
2 1 2 3
2 2 3 1
2 2 3 2
2 2 3 3
2 2 1 1
2 2 1 2
2 2 1 3
2 2 2 1
2 2 2 2
2 2 2 3
2 2 3 1
2 2 3 2
2 2 3 3
2 3 1 1
2 3 1 2
2 3 1 3
2 3 2 1
2 3 2 2
2 3 2 3
2 3 3 1
2 3 3 2
2 3 3 3

3 1 1 1
3 1 1 2
3 1 1 3
3 1 2 1
3 1 2 2
3 1 2 3
3 2 3 1
3 2 3 2
3 2 3 3
3 2 1 1
3 2 1 2
3 2 1 3
3 2 2 1
3 2 2 2
3 2 2 3
3 2 3 1
3 2 3 2
3 2 3 3
3 3 1 1
3 3 1 2
3 3 1 3
3 3 2 1
3 3 2 2
3 3 2 3
3 3 3 1
3 3 3 2
3 3 3 3

You could continue it until you see my answer is correct

 

[eltaylor001]

Sorry am in need of sleep, still catching up from my long weekend in stockholm. Been ages since worked with this stuff anyway. I unfortunately showed the permutations from picking 3 items out of 8 possible items. Where you're actually picking 1 item from 3 items 8 times.